If you have vba int functional error on your machine, this user manual should help you.
Approved: Fortect
VBA Int function failed. If the Int function returns with a value that cannot be interpreted as a number, it returns an error: Runtime error ’13’: Type conflict. Return to VBA functions page
protocol
- 2 to read
Syntax
A required numeric argument is a double and / or l Any valid numeric expression. If the number contains zero, zero is returned.
Int and Fix remove the fractional number and then return the resulting integer value.
The difference between Int and Fix is that for negative numbers, Int returns the first non-constructive integer less than or equal to Quantity, while Fix returns the first negative integer incremented to or equal to a number. This example converts Int -8.4 to -9, Fix and converts -8.4 to -8.
Example
Approved: Fortect
Fortect is the world's most popular and effective PC repair tool. It is trusted by millions of people to keep their systems running fast, smooth, and error-free. With its simple user interface and powerful scanning engine, Fortect quickly finds and fixes a broad range of Windows problems - from system instability and security issues to memory management and performance bottlenecks.
This example shows how the Int and Fix functions return the integer portions of numbers. When you print a negative number argument, Int returns the first negative integer less than or equal to the number; This fix function returns the first unwanted integer greater than or equal to that number.
Dim MyNumberMyNumber = Int (99,8) no Returns 99.MyNumber = Fix (99.2) Returns '99.MyNumber = Int (-99,8) Returns -100.MyNumber = Fix (-99,8) Returns -99.MyNumber = Int (-99. 2) 'Returns -100.MyNumber means Fix (-99.2) 'Returns -99.
See Also
Support & Feedback
Do you have any questions or ideas about VBA Office or this documentation? See Office VBA Support and Feedback for instructions on how to get help and provide feedback.
Description
The VBA int function rounds the specified number down to a large integer.
That is, positive numbers are rounded towards , and negative numbers are rounded away from zero.
If the Number argument is a number, that’s all you need for the entire section.
VBA Int Int Function Examples
- the function has a positive number from 77.7 to the integer seventy-seven (that is, from to zero);
- Int efforts are negative – 77. rounded. Much more like the integer -78 (i.e. far from zero).
VBA-Int Function Error
If the int clause returns with a value that cannot be interpreted as a number, it should return an error:
I am doing likes counting with Microsoft Excel vba.
INT (151,2 * 100)
I see that the result is the calculation 15119, but the correct result should be 15220.
I hope I usually remove INT () 151.2 * 100
The returned result is slanted towards 15220.
Can anyone tell why there is a difference and if the restore just removes INT () to get the correct result?
52.9k
requested October 10, 2011 6:51 AM
611
Not The Answer You’re Looking For? Check Out Other Questions Tagged By Vba Or Assask Your Question.
a = (151,2 100)Seal * Int (a)15119Click15120Print a = 15120Wrong
There is no double precision number to accurately represent the result as 15120, like 151.2 * 100 . The next one is obviously just below 15120. If you specify Int , it will be truncated, that is, rounded to 15119.
Cint (a)15120Print tour (s)15120
Note: if you have a variable i of type Integer and you only say i = 151.2 * 100 as your company suggests, you are applying implicitly, because that the result is an integer, i.e. let’s say without question i = CInt (151,2 * 100) . I think it’s best to be frank.
answered Oct 10. ’11, maybe 8:04
Speed up your computer's performance now with this simple download.
